You don't explain the labeling very well, but I get that
AC is divided into 5+11
CE is divided into 11+4
AE is divided into 4+5
TRIANGLE ACE IS A CIRCUMSCRIBED TRIANGLE. POINTS B,D AND F ARE POINTS OF TANGENCY . IF AC= 16 AND AE= 9 CM AND CE = 15 CM FIND AD, FE, AND CD.
Thank you very mych
5 answers
but whats x ?
Who knows ?
You don't mention x in your description.
You don't mention where B, D, and F are located, but I must have labeled mine the same way as Steve, since I got his answers as well.
What still has to be found is AD
In triangle ACE
9^2 = 16^2 + 15^2 - 2(15)(16)cosC
you should get cosC = 5/6
(don't find the actual angle)
in triangle ACD
AD^2 = 11^2 + 16^2 - 2(11)(16)cosC
= 251/3
AD = √(251/3) or appr 9.15
You don't mention x in your description.
You don't mention where B, D, and F are located, but I must have labeled mine the same way as Steve, since I got his answers as well.
What still has to be found is AD
In triangle ACE
9^2 = 16^2 + 15^2 - 2(15)(16)cosC
you should get cosC = 5/6
(don't find the actual angle)
in triangle ACD
AD^2 = 11^2 + 16^2 - 2(11)(16)cosC
= 251/3
AD = √(251/3) or appr 9.15
I assumed AD was a typo, or due to label discrepancy, since the subject is the tangents, which are of length 4,5,11.
How do you find 4,5, and 11 though?
1 answer