Triangle ABC is reflected across the x -axis. If the coordinates of the original shape are A(−4,−1) , B(−5,−2) , and C(−10,−1) , what are the coordinates of A′ , B′ , and C′ ?(1 point) Responses A′(4,1) , B′(5,2) , and C′(10,1) upper A prime left parenthesis 4 comma 1 right parenthesis , upper B prime left parenthesis 5 comma 2 right parenthesis , and upper C prime left parenthesis 10 comma 1 right parenthesis A′(−4,1) , B′(−5,2) , and C′(−10,1) upper A prime left parenthesis negative 4 comma 1 right parenthesis , upper B prime left parenthesis negative 5 comma 2 right parenthesis , and upper C prime left parenthesis negative 10 comma 1 right parenthesis A′(−4,1) , B′(5,−2) , and C′(−10,1) upper A prime left parenthesis negative 4 comma 1 right parenthesis , upper B prime left parenthesis 5 comma negative 2 right parenthesis , and upper C prime left parenthesis negative 10 comma 1 right parenthesis A′(4,−1) , B′(5,−2) , and C′(10,−1)
1 answer
When a point \((x, y)\) is reflected across the x-axis, its new coordinates become \((x, -y)\).
Let's apply this to each point of triangle ABC:
For point \(A(-4, -1)\): \[ A' = (-4, -(-1)) = (-4, 1) \]
For point \(B(-5, -2)\): \[ B' = (-5, -(-2)) = (-5, 2) \]
For point \(C(-10, -1)\): \[ C' = (-10, -(-1)) = (-10, 1) \]
Thus, the coordinates of the reflected triangle are:
So, the correct response is: A′(−4,1), B′(−5,2), and C′(−10,1).
