Question

Triangle ABC is reflected across the x -axis. If the coordinates of the original shape are A(−4,−1) , B(−5,−2) , and C(−10,−1) , what are the coordinates of A′ , B′ , and C′ ?(1 point) Responses A′(4,−1) , B′(5,−2) , and C′(10,−1) upper A prime left parenthesis 4 comma negative 1 right parenthesis , upper B prime left parenthesis 5 comma negative 2 right parenthesis , and upper C prime left parenthesis 10 comma negative 1 right parenthesis A′(−4,1) , B′(5,−2) , and C′(−10,1) upper A prime left parenthesis negative 4 comma 1 right parenthesis , upper B prime left parenthesis 5 comma negative 2 right parenthesis , and upper C prime left parenthesis negative 10 comma 1 right parenthesis A′(−4,1) , B′(−5,2) , and

Answer 1

When a point \((x, y)\) is reflected across the x-axis, the coordinates become \((x, -y)\).

Given the points:

• A\((-4, -1)\)
• B\((-5, -2)\)
• C\((-10, -1)\)

We apply the reflection:

1. For A\((-4, -1)\): \[ A' = (-4, -(-1)) = (-4, 1) \]

2. For B\((-5, -2)\): \[ B' = (-5, -(-2)) = (-5, 2) \]

3. For C\((-10, -1)\): \[ C' = (-10, -(-1)) = (-10, 1) \]

Thus, the coordinates after the reflection are:

• A'\((-4, 1)\)
• B'\((-5, 2)\)
• C'\((-10, 1)\)

Therefore, the correct response is: A′(−4, 1), B′(−5, 2), and C′(−10, 1).