Triangle ABC is reflected across the x -axis. If the coordinates of the original shape are A(−4,−1) , B(−5,−2) , and C(−10,−1) , what are the coordinates of A′ , B′ , and C′ ?(1 point) Responses A′(4,−1), B′(5,−2), and C′(10,−1) upper A prime left parenthesis 4 comma negative 1 right parenthesis , upper B prime left parenthesis 5 comma negative 2 right parenthesis , and upper C prime left parenthesis 10 comma negative 1 right parenthesis A′(−4,1), B′(5,−2), and C′(−10,1) upper A prime left parenthesis negative 4 comma 1 right parenthesis , upper B prime left parenthesis 5 comma negative 2 right parenthesis , and upper C prime left parenthesis negative 10 comma 1 right parenthesis A′(4,1), B′(5,2), and C′(10,1) upper A prime left parenthesis 4 comma 1 right parenthesis , upper B prime left parenthesis 5 comma 2 right parenthesis , and upper C prime left parenthesis 10 comma 1 right parenthesis A′(−4,1), B′(−5,2), and C′(−10,1)
1 answer
When a point \((x, y)\) is reflected across the x-axis, the new coordinates become \((x, -y)\).
Let's apply this to each of the points:
For point A \((-4, -1)\): \[ A' = (-4, -(-1)) = (-4, 1) \]
For point B \((-5, -2)\): \[ B' = (-5, -(-2)) = (-5, 2) \]
For point C \((-10, -1)\): \[ C' = (-10, -(-1)) = (-10, 1) \]
So the coordinates of the reflected points are:
Thus, the correct response is: A′(−4,1), B′(−5,2), and C′(−10,1).
