The centroid of a triangle can be found by averaging the coordinates of its vertices. For triangle ABC with vertices \( A(-2, -3) \), \( B(1, 0) \), and \( C(-2, 2) \), we can calculate the centroid \( G(x, y) \) as follows:
\[ G_x = \frac{x_A + x_B + x_C}{3} \] \[ G_y = \frac{y_A + y_B + y_C}{3} \]
Calculating the \( x \)-coordinate of the centroid:
\[ G_x = \frac{-2 + 1 - 2}{3} = \frac{-3}{3} = -1 \]
Now calculating the \( y \)-coordinate of the centroid:
\[ G_y = \frac{-3 + 0 + 2}{3} = \frac{-1}{3} \]
Combining these, we find the coordinates of the centroid \( G \):
\[ G\left(-1, -\frac{1}{3}\right) \]
Thus, the centroid of triangle ABC is at the point \( (-1, -\frac{1}{3}) \), and all three medians of the triangle meet at this single point.
Since the options given do not include \( (-1, -\frac{1}{3}) \), the options seem to be incorrect based on the calculation of the centroid. The correct answer is \( (-1, -\frac{1}{3}) \).