What, you can't draw a triangle ABC and an altitude CD?
You are doomed...
5.3/AD = tan46°
AC^2 = AD^2 + 5.3^2
Triangle ABC has <BAC=46° and <ABC=54°. An altitude (perpendicular line) is drawn from C to meet AB at point D. If the altitude is 5.3cm long, find, correct to 1 d.p. the length of:
a) AC
Just require help drawing the diagram.
3 answers
Don't think you read the part where I needed help drawing the diagram, but thanks for helping anyways.
yeah, I read it. Why do you think I expressed astonishment that you could not draw a simple triangle with angles labeled A,B,C ?
The angle don't have to be exact. It's just a diagram to work with. You know what a 45° angle looks like, I hope. Both angles A and B are fairly close to that.
The angle don't have to be exact. It's just a diagram to work with. You know what a 45° angle looks like, I hope. Both angles A and B are fairly close to that.