Triangle ABC

has vertices point A(−2,−2)
, point B(−4,−3)
, and point C(−2,−5)
. Find the coordinates of A′
, B′
, and C′
after a dilation with a scale factor of 3
and a center point of dilation at the origin.(2 points)
A′=
(
)
B′=
(
)
C′=
(
)

1 answer

To find the coordinates of the points A', B', and C' after a dilation centered at the origin with a scale factor of 3, we can use the dilation formula:

\[ (x', y') = (k \cdot x, k \cdot y) \]

where \( k \) is the scale factor, and \((x, y)\) are the original coordinates of the point.

Given:

  • A(−2,−2)
  • B(−4,−3)
  • C(−2,−5)
  • Scale factor \( k = 3 \)

Now we will calculate the new coordinates for each point:

  1. For point A(−2,−2): \[ A' = (3 \cdot -2, 3 \cdot -2) = (-6, -6) \]

  2. For point B(−4,−3): \[ B' = (3 \cdot -4, 3 \cdot -3) = (-12, -9) \]

  3. For point C(−2,−5): \[ C' = (3 \cdot -2, 3 \cdot -5) = (-6, -15) \]

Thus, the coordinates after dilation are:

  • \( A' = (-6, -6) \)
  • \( B' = (-12, -9) \)
  • \( C' = (-6, -15) \)

Final answers:

  • A′ = (-6, -6)
  • B′ = (-12, -9)
  • C′ = (-6, -15)