Triangle ABC has vertices point A(2,1), point B(4,3), and point C(−2,5). Find the coordinates of A′, B′, and C′ after a dilation with a scale factor of 7 and a center point of dilation at the origin (0,0).(2 points)

A′= (
)
B′= (
)
C′= (
)

1 answer

To find the coordinates of A', B', and C' after a dilation with a scale factor of 7 and a center point of dilation at the origin (0,0), we need to multiply the x and y coordinates of each vertex by the scale factor.

For vertex A(2,1):
A' = (scale factor * x coordinate of A, scale factor * y coordinate of A)
= (7 * 2, 7 * 1)
= (14, 7)

For vertex B(4,3):
B' = (scale factor * x coordinate of B, scale factor * y coordinate of B)
= (7 * 4, 7 * 3)
= (28, 21)

For vertex C(-2,5):
C' = (scale factor * x coordinate of C, scale factor * y coordinate of C)
= (7 * -2, 7 * 5)
= (-14, 35)

Therefore, the coordinates of A' are (14, 7), the coordinates of B' are (28, 21), and the coordinates of C' are (-14, 35).