To find the length of CD, we can use trigonometry.
First, we need to find the lengths of AC and BC using the sine rule:
AC/sin 30 = 10/sin 45
AC = 10 * sin 30 / sin 45
AC ≈ 5.77 cm
BC = 10 - AC
BC ≈ 4.23 cm
Now, we can use the sine rule in triangle ACD to find the length of CD:
CD/sin 45 = BC/sin 30
CD = BC * sin 45 / sin 30
CD ≈ 3.09 cm
Therefore, the length of CD is approximately 3.09 cm.
Triangle ABC =10cm angle abc=30 and angleBAC= 45. A perpendicular from C to meet ABatD
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