Let's assume that Trey drives x miles.
For the first plan, the cost would be 0.90x.
For the second plan, the cost would be 50+(0.80)x = 0.80x + 50.
To find the number of miles where the two plans cost the same, we set the two costs equal to each other: 0.90x = 0.80x + 50.
Subtracting 0.80x from both sides, we get 0.10x = 50.
Dividing both sides by 0.10, we find that x = 500.
Thus, Trey would need to drive 500 miles for the two plans to cost the same. Answer: \boxed{500}.
Trey will rent a car for the weekend. He can choose one of two plans. The first plan has no initial fee but costs $0.90 per mile driven. The second plan has an initial fee of $50 and costs an additional $0.80 per mile driven. How many miles would Trey need to drive for the two plans to cost the same?
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