Trevor invests $10000 for a year.he obtains 8% per year for a part of the money and 10%per an um for remainder.at end of the year he sill receive $950 in interest.how much does he invest at 10%

Answer 1

If $x at 10%, the rest $(1000-x) is at 8%. So, add up the interest

.10x + .08(10000-x) = 950