Trend Lines Quick Check
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Question
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A scatterplot graph shows x-axis ranging from 0 to 50 and y-axis ranging from 0 to 10. Multiple points are plotted around a line that points downward to the right with an arrowhead on the bottom.
The x-axis is drawn in increments of 5 but labeled in increments of 10. The y-axis is drawn in increments of 1 but labeled in increments of 2. The line passes approximately through left parenthesis 0 comma 8 right parenthesis, left parenthesis 10 comma 6 right parenthesis, left parenthesis 15 comma 5 right parenthesis, left parenthesis 20 comma 4 right parenthesis, left parenthesis 25 comma three right parenthesis, and left parenthesis 40 comma 0 right parenthesis. 14 points are plotted close to or on the line.
Write an equation in slope-intercept form of the trend line.
(1 point)
Responses
y=−15x+8
y equals negative Start Fraction 1 over 5 End Fraction x plus 8
y=5.67x+8
y equals 5.67 x plus 8
y=−15x+3
y equals negative Start Fraction 1 over 5 End Fraction x plus 3
y=15x+8
y equals Start Fraction 1 over 5 End Fraction x plus 8
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9 answers
y = -0.2x + 8
y = -0.2x + 8
Looking at the points provided in the scatterplot: (0,8), (10,6), (15,5), (20,4), (25,3), and (40,0), we can see a trend line that appears to have a slope of -0.2 and a y-intercept of 8.
Therefore, the correct equation in slope-intercept form of the trend line is:
y = -0.2x + 8
I hope this clears up any confusion. Thank you for your patience.
Points on the trend line: (0,8), (10,6), (15,5), (20,4), (25,3), and (40,0)
Calculating the slope using the points (0,8) and (40,0):
m = (0 - 8) / (40 - 0) = -8 / 40 = -0.2
Using the point-slope form with the point (0,8):
y - 8 = -0.2(x - 0)
y - 8 = -0.2x
y = -0.2x + 8
Therefore, the correct equation in slope-intercept form of the trend line is:
y = -0.2x + 8
Thank you for your patience, and I appreciate you pointing out the errors.