To write the equation of the trend line in slope-intercept form, we need to find the slope and the y-intercept.
1. Find the slope using two points on the line:
Let's use the points (0, 45) and (4.5, 0).
slope = (y2 - y1) / (x2 - x1)
slope = (0 - 45) / (4.5 - 0)
slope = -45 / 4.5
slope = -10
2. Use the slope and one of the points to find the y-intercept:
Let's use the point (0, 45).
y = mx + b (where m is the slope and b is the y-intercept)
45 = -10(0) + b
45 = b
3. Write the equation in slope-intercept form with the slope and y-intercept:
y = -10x + 45
Therefore, the equation of the trend line in slope-intercept form is y = -10x + 45.
Trend Lines Practice
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Question
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An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 50 in increments of 10. Multiple points are plotted around a line that points downward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 45 right parenthesis, left parenthesis 2 comma 25 right parenthesis, left parenthesis 3 comma 15 right parenthesis, and left parenthesis 4.5 comma 0 right parenthesis. 13 points are plotted close to the line.
Write an equation in slope-intercept form of the trend line.
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