Trend Lines Practice

Complete this assessment to review what you've learned. It will not count toward your grade.
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Question
Use the image to answer the question.

An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 30 in increments of 2. Multiple points are plotted around a line that points upward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 12 right parenthesis, left parenthesis 4 comma 16 right parenthesis, and left parenthesis 6 comma 18 right parenthesis. 12 points are plotted close to the line.

Write an equation in slope-intercept form of the trend line.

(1 point)
y=
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1 answer

To find the equation of the trend line, we need to determine the slope and y-intercept.

To find the slope, we can use the formula:

slope = (change in y)/(change in x)

Using the points (0, 12) and (6, 18), the change in y is 18 - 12 = 6 and the change in x is 6 - 0 = 6. Therefore, the slope is 6/6 = 1.

Next, we can use the slope-intercept form of a line, y = mx + b, where m is the slope and b is the y-intercept.

Using the point (0, 12), we can substitute the values into the equation to solve for b:

12 = 1(0) + b
12 = b

Therefore, the y-intercept is 12.

Now we can write the equation of the trend line:

y = 1x + 12

Simplifying, we get:

y = x + 12