Asked by hrsdptmsshch (supernatural)
Trapezoid upper A upper B upper C upper D with parallel sides upper A upper B and upper C upper D.
ABCD is a trapezoid with AB¯¯¯¯¯¯¯¯∥CD¯¯¯¯¯¯¯¯ where AD=8x+7 and BC=2x+28 . For what value of x is ABCD an isosceles trapezoid?
(1 point)
Responses
14.5
14.5
3.5
3.5
5.5
5.5
15
ABCD is a trapezoid with AB¯¯¯¯¯¯¯¯∥CD¯¯¯¯¯¯¯¯ where AD=8x+7 and BC=2x+28 . For what value of x is ABCD an isosceles trapezoid?
(1 point)
Responses
14.5
14.5
3.5
3.5
5.5
5.5
15
Answers
There are no human answers yet.
Answered by
GPT-4o mini
In an isosceles trapezoid, the lengths of the non-parallel sides (the legs) are equal. In this case, that means we need to set the lengths of AD and BC equal to each other:
\[
AD = BC
\]
Substituting the expressions for AD and BC:
\[
8x + 7 = 2x + 28
\]
Now, we will solve for \(x\).
1. Subtract \(2x\) from both sides:
\[
8x - 2x + 7 = 28
\]
This simplifies to:
\[
6x + 7 = 28
\]
2. Next, subtract 7 from both sides:
\[
6x = 28 - 7
\]
This simplifies to:
\[
6x = 21
\]
3. Now, divide both sides by 6:
\[
x = \frac{21}{6} = 3.5
\]
Thus, the value of \(x\) for which \(ABCD\) is an isosceles trapezoid is \( \boxed{3.5} \).
\[
AD = BC
\]
Substituting the expressions for AD and BC:
\[
8x + 7 = 2x + 28
\]
Now, we will solve for \(x\).
1. Subtract \(2x\) from both sides:
\[
8x - 2x + 7 = 28
\]
This simplifies to:
\[
6x + 7 = 28
\]
2. Next, subtract 7 from both sides:
\[
6x = 28 - 7
\]
This simplifies to:
\[
6x = 21
\]
3. Now, divide both sides by 6:
\[
x = \frac{21}{6} = 3.5
\]
Thus, the value of \(x\) for which \(ABCD\) is an isosceles trapezoid is \( \boxed{3.5} \).
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