You are given both A and C.
So the length of AC = √( 0-(-5))^2 + (3-6)^2 )
AC = ...
your turn
Trapezoid ABCD is formed by
A(–7,3), B(–5,6), C(0,6), and D(0,3).
Determine the length of the diagonal AC in trapezoid ABCD. Round to the nearest tenth and show all of your work.
Please help me!
;-;
4 answers
12?
Sorry I had a typo , used the wrong point
AC = √( 0-(-7))^2 + (6-3)^2 )
= √(49 + 9) = √58
no way to get 12, either way
AC = √( 0-(-7))^2 + (6-3)^2 )
= √(49 + 9) = √58
no way to get 12, either way
whats the answer
10 answers