To find \( P(A \text{ and } B) \), we need to determine the probability of both events happening: an on-time arrival (event A) and transportation by bus (event B).
First, let's identify the number of on-time arrivals using a bus from the table provided:
- Total number of on-time arrivals by bus = 46
Next, we need to determine the total number of events (total number of transports):
- Total transports = 320
Now we can calculate \( P(A \text{ and } B) \):
\[ P(A \text{ and } B) = \frac{\text{Number of on-time bus arrivals}}{\text{Total number of transports}} = \frac{46}{320} \]
Now let's calculate the fraction:
\[ \frac{46}{320} = 0.14375 \]
When rounding to the nearest hundredth:
\[ P(A \text{ and } B) \approx 0.14 \]
Therefore, the answer is:
0.14