x at .1 and y at .08
y = 10,000-x
.1x + .08y = 840
so substitute
.1x + .08 (10,000-x) = 840
Translate the problem into a pair of linear equations in two variables. Solve the equations using either elimination or substitution. State your answer for the specified variable.
A student took out two loans totaling $10,000 to help pay for college expenses. One loan was at 8% simple interest, and the other was at 10%. After one year, the student owed $840 in interest. Find the amount of the loan at 10%.
3 answers
x + y = 10000
.1x + .08y = 840
suggestion:
multiply the second by 100
then the first by 8 and subtract them
.1x + .08y = 840
suggestion:
multiply the second by 100
then the first by 8 and subtract them
Thanks!! You are all the best.