Translate quadrilateral ADCB 5 units to the left and 2 units down. What are the coordinates of new quadrilateral A′D′C′B′ ?

Answer 1

To translate quadrilateral ADCB 5 units to the left and 2 units down, you will subtract 5 from the x-coordinates of the vertices and 2 from the y-coordinates of the vertices.

Let's say the coordinates of the original quadrilateral \(A\), \(D\), \(C\), and \(B\) are as follows:

• \(A(x_1, y_1)\)
• \(D(x_2, y_2)\)
• \(C(x_3, y_3)\)
• \(B(x_4, y_4)\)

After translating, the new coordinates will be:

• \(A'(x_1 - 5, y_1 - 2)\)
• \(D'(x_2 - 5, y_2 - 2)\)
• \(C'(x_3 - 5, y_3 - 2)\)
• \(B'(x_4 - 5, y_4 - 2)\)

If you provide the specific coordinates of the vertices of quadrilateral ADCB, I can calculate the coordinates of the new quadrilateral \(A'D'C'B'\).