The correct answer is 6,0.
To find the new coordinates of P', you simply need to subtract 6 from the x-coordinate and add 2 to the y-coordinate of P.
P(8,2) -> P'(8-2,2-6) -> P'(6,0)
Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P’?
2,0
2,12
6,0
10,4
1 answer