Transition metals (also called heavy metals) form insoluble compounds with hydroxide ions. Therefore, it is possible to extract heavy metal ions from water by raising the pH. The precipitation reaction between cadmium(II) and hydroxide is shown below.
Cd2+(aq) + 2OH−(aq) → Cd(OH)2(s)
If you had a 0.250L solution containing 0.0130M of Cd2+(aq), and you wished to add enough 1.29M NaOH(aq) to precipitate all of the metal, what is the minimum amount of the NaOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH−(aq) for the precipitation.
How can I set this up? I have part of it set up but I'm not coming out right.
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