transform the liner equation -2y=14-6 to slop-intercept form

Answer 1

To transform the linear equation -2y = 14 - 6 into slope-intercept form, we need to isolate y on one side of the equation.

First, let's simplify the right side of the equation:
-2y = 14 - 6
-2y = 8

Next, divide both sides of the equation by -2 to solve for y:
(-2y) / -2 = 8 / -2
y = -4

Thus, the equation -2y = 14 - 6 can be written in slope-intercept form as y = -4.

Answer 2

opps i meant transform the liner equation -2y=14-6x to slop-intercept form

Answer 3

To transform the linear equation -2y = 14 - 6x into slope-intercept form (y = mx + b), we need to isolate y on one side of the equation.

First, let's simplify the right side of the equation:
-2y = 14 - 6x

Next, divide both sides of the equation by -2 to solve for y:
(-2y) / -2 = (14 - 6x) / -2
y = -7 + 3x

Thus, the equation -2y = 14 - 6x can be written in slope-intercept form as y = 3x - 7.