To transform the linear equation \(4x - 8y = 24\) into slope-intercept form, which is \(y = mx + b\) where \(m\) is the slope and \(b\) is the y-intercept, we need to solve for \(y\).
Starting with the original equation:
\[ 4x - 8y = 24 \]
- Subtract \(4x\) from both sides:
\[ -8y = -4x + 24 \]
- Divide every term by \(-8\):
\[ y = \frac{-4}{-8}x + \frac{24}{-8} \]
This simplifies to:
\[ y = \frac{1}{2}x - 3 \]
So, the slope-intercept form of the equation is:
\[ y = \frac{1}{2}x - 3 \]
This corresponds to the response \(y = \frac{1}{2}x - 3\).