To transform the equation 10x - 2y = -3 into slope-intercept form, we need to isolate y on one side of the equation.
First, let's start by subtracting 10x from both sides:
-2y = -10x - 3
Next, divide both sides by -2 to solve for y:
y = 5x + (3/2)
Therefore, the equation in slope-intercept form is y = 5x + 3/2.
Transform 10x+-2y=-3 into slope-intercept form
y=?x+?
11 answers
Transform-8x+5y=-4 into slope-intercept form
y=?x+?
y=?x+?
To transform the equation -8x + 5y = -4 into slope-intercept form, we need to isolate y on one side of the equation.
First, let's start by adding 8x to both sides:
5y = 8x - 4
Next, divide both sides by 5 to solve for y:
y = (8/5)x - 4/5
Therefore, the equation in slope-intercept form is y = (8/5)x - 4/5.
First, let's start by adding 8x to both sides:
5y = 8x - 4
Next, divide both sides by 5 to solve for y:
y = (8/5)x - 4/5
Therefore, the equation in slope-intercept form is y = (8/5)x - 4/5.
Using two points, graph y=-3x+5
To graph the equation y = -3x + 5 using two points, we can choose any two values for x and find their corresponding y-values.
1. Let's choose x = 0:
When x = 0, y = -3(0) + 5 = 5
So we have the point (0, 5).
2. Let's choose x = 2:
When x = 2, y = -3(2) + 5 = -1
So we have the point (2, -1).
Now we can plot these two points on a graph and draw a straight line passing through them. The graph should look like this:
```
|
6 |
|
5 | x
|
4 |
|
3 |
|
2 | x
|
1 |
|
-1 | x
|_________________________
0 1 2 3 4 5 6
```
The line passes through the points (0, 5) and (2, -1), and it represents the equation y = -3x + 5.
1. Let's choose x = 0:
When x = 0, y = -3(0) + 5 = 5
So we have the point (0, 5).
2. Let's choose x = 2:
When x = 2, y = -3(2) + 5 = -1
So we have the point (2, -1).
Now we can plot these two points on a graph and draw a straight line passing through them. The graph should look like this:
```
|
6 |
|
5 | x
|
4 |
|
3 |
|
2 | x
|
1 |
|
-1 | x
|_________________________
0 1 2 3 4 5 6
```
The line passes through the points (0, 5) and (2, -1), and it represents the equation y = -3x + 5.
Using two points, graph y=2/7x-4
To graph the equation y = (2/7)x - 4 using two points, we can choose any two values for x and find their corresponding y-values.
1. Let's choose x = 0:
When x = 0, y = (2/7)(0) - 4 = -4
So we have the point (0, -4).
2. Let's choose x = 7:
When x = 7, y = (2/7)(7) - 4 = 2 - 4 = -2
So we have the point (7, -2).
Now we can plot these two points on a graph and draw a straight line passing through them. The graph should look like this:
```
|
2 |
| x
-2 |
|
-4 | x
|
-6 |
|
-8 |
|_________________________
0 2 4 6 8 10 12
```
The line passes through the points (0, -4) and (7, -2), and it represents the equation y = (2/7)x - 4.
1. Let's choose x = 0:
When x = 0, y = (2/7)(0) - 4 = -4
So we have the point (0, -4).
2. Let's choose x = 7:
When x = 7, y = (2/7)(7) - 4 = 2 - 4 = -2
So we have the point (7, -2).
Now we can plot these two points on a graph and draw a straight line passing through them. The graph should look like this:
```
|
2 |
| x
-2 |
|
-4 | x
|
-6 |
|
-8 |
|_________________________
0 2 4 6 8 10 12
```
The line passes through the points (0, -4) and (7, -2), and it represents the equation y = (2/7)x - 4.
graph y=3/2x-4 and y=-7/2x+6
To graph the equations y = (3/2)x - 4 and y = (-7/2)x + 6, we can start by selecting several x-values and calculating the corresponding y-values for each equation, and then plotting them on a graph.
Let's choose x = -2, -1, 0, 1, and 2.
For the equation y = (3/2)x - 4:
When x = -2:
y = (3/2)(-2) - 4 = -6 - 4 = -10
So we have the point (-2, -10).
When x = -1:
y = (3/2)(-1) - 4 = -3/2 - 4 = -11/2
So we have the point (-1, -11/2).
When x = 0:
y = (3/2)(0) - 4 = 0 - 4 = -4
So we have the point (0, -4).
When x = 1:
y = (3/2)(1) - 4 = 3/2 - 4 = -5/2
So we have the point (1, -5/2).
When x = 2:
y = (3/2)(2) - 4 = 6/2 - 4 = -2
So we have the point (2, -2).
For the equation y = (-7/2)x + 6:
When x = -2:
y = (-7/2)(-2) + 6 = 7 + 6 = 13
So we have the point (-2, 13).
When x = -1:
y = (-7/2)(-1) + 6 = 7/2 + 6 = 19/2
So we have the point (-1, 19/2).
When x = 0:
y = (-7/2)(0) + 6 = 0 + 6 = 6
So we have the point (0, 6).
When x = 1:
y = (-7/2)(1) + 6 = -7/2 + 6 = 5/2
So we have the point (1, 5/2).
When x = 2:
y = (-7/2)(2) + 6 = -7 + 6 = -1
So we have the point (2, -1).
Now we can plot these points on a graph:
```
|
14 |
13 |
12 |
11 |
10 |
9 |
8 |
7 | x
6 | x
5 | x
4 |
3 |
2 | x
1 |
0 |
-1 |
-2 |
-3 |
-4 |
-5 |
S_________________________
-2 -1 0 1 2 3 4 5 6
```
The blue line represents the equation y = (3/2)x - 4, and the orange line represents the equation y = (-7/2)x + 6.
Let's choose x = -2, -1, 0, 1, and 2.
For the equation y = (3/2)x - 4:
When x = -2:
y = (3/2)(-2) - 4 = -6 - 4 = -10
So we have the point (-2, -10).
When x = -1:
y = (3/2)(-1) - 4 = -3/2 - 4 = -11/2
So we have the point (-1, -11/2).
When x = 0:
y = (3/2)(0) - 4 = 0 - 4 = -4
So we have the point (0, -4).
When x = 1:
y = (3/2)(1) - 4 = 3/2 - 4 = -5/2
So we have the point (1, -5/2).
When x = 2:
y = (3/2)(2) - 4 = 6/2 - 4 = -2
So we have the point (2, -2).
For the equation y = (-7/2)x + 6:
When x = -2:
y = (-7/2)(-2) + 6 = 7 + 6 = 13
So we have the point (-2, 13).
When x = -1:
y = (-7/2)(-1) + 6 = 7/2 + 6 = 19/2
So we have the point (-1, 19/2).
When x = 0:
y = (-7/2)(0) + 6 = 0 + 6 = 6
So we have the point (0, 6).
When x = 1:
y = (-7/2)(1) + 6 = -7/2 + 6 = 5/2
So we have the point (1, 5/2).
When x = 2:
y = (-7/2)(2) + 6 = -7 + 6 = -1
So we have the point (2, -1).
Now we can plot these points on a graph:
```
|
14 |
13 |
12 |
11 |
10 |
9 |
8 |
7 | x
6 | x
5 | x
4 |
3 |
2 | x
1 |
0 |
-1 |
-2 |
-3 |
-4 |
-5 |
S_________________________
-2 -1 0 1 2 3 4 5 6
```
The blue line represents the equation y = (3/2)x - 4, and the orange line represents the equation y = (-7/2)x + 6.
Two points only
If we are only using two points to graph the equations y = (3/2)x - 4 and y = (-7/2)x + 6, we can select any two values for x and calculate the corresponding y-values for each equation.
Let's choose x = 0 and x = 4.
For the equation y = (3/2)x - 4:
When x = 0:
y = (3/2)(0) - 4 = 0 - 4 = -4
So we have the point (0, -4).
When x = 4:
y = (3/2)(4) - 4 = 6 - 4 = 2
So we have the point (4, 2).
For the equation y = (-7/2)x + 6:
When x = 0:
y = (-7/2)(0) + 6 = 0 + 6 = 6
So we have the point (0, 6).
When x = 4:
y = (-7/2)(4) + 6 = -14 + 6 = -8
So we have the point (4, -8).
Now we can plot these two points on a graph:
```
|
10 |
9 |
8 |
7 |
6 | x
5 |
4 | x
3 |
2 |
1 |
0 |
-1 |
-2 |
-3 |
-4 |
S_________________________
-2 -1 0 1 2 3 4 5 6
```
The blue point represents the point (0, -4) for the equation y = (3/2)x - 4, and the orange point represents the point (4, -8) for the equation y = (-7/2)x + 6.
Let's choose x = 0 and x = 4.
For the equation y = (3/2)x - 4:
When x = 0:
y = (3/2)(0) - 4 = 0 - 4 = -4
So we have the point (0, -4).
When x = 4:
y = (3/2)(4) - 4 = 6 - 4 = 2
So we have the point (4, 2).
For the equation y = (-7/2)x + 6:
When x = 0:
y = (-7/2)(0) + 6 = 0 + 6 = 6
So we have the point (0, 6).
When x = 4:
y = (-7/2)(4) + 6 = -14 + 6 = -8
So we have the point (4, -8).
Now we can plot these two points on a graph:
```
|
10 |
9 |
8 |
7 |
6 | x
5 |
4 | x
3 |
2 |
1 |
0 |
-1 |
-2 |
-3 |
-4 |
S_________________________
-2 -1 0 1 2 3 4 5 6
```
The blue point represents the point (0, -4) for the equation y = (3/2)x - 4, and the orange point represents the point (4, -8) for the equation y = (-7/2)x + 6.