Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per huors and train B is traveling at 110 miles per hours. Train A passes a station at 1:100pm if train B passes the same station at 1:22 pm at what time will train B catch up to train A?

Question

when will Train B catch up with train A?

Answer 1

Train A passes the station at 13:00 and train B passes at 13:22. Train A has a headway of 22 minutes, which translates into 100 mph*22/60 = 36.67 miles
Speed of train B exceeds that of train by (110-100)=10 mph.
Therefore time to catch-up
= 36.67/10 *60 minutes
= 220 minutes after 13:22
Therefore time when train B catches up with train A
= 13:22 + 220 minutes
= 17:02

Answer 2

Question on Train A should be 13:10 does this change the equation.
Please help

Answer 3

Yes, it does. Sorry.
Could you figure out along the lines of my solution and post your results for checking, if you wish?

Answer 4

so A=13:10
B=13:22
100mph *12/.60= 20miles
(110-100)=10mph
=20/10*60
120 after 13:22

I'm lost after that
=13:22+120
=

Answer 5

It's 120 minutes after 13:22, or
13:22 + 2:00
= 15:22