Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hr abd train B is traveling at 90 miles per hr. Train A passes a station at 3:25am,if train B passes the same station at 3:37am, at what time will train B catch up train A???

Answer 1

At 3:37 train A has a lead of 2 minutes, or translated into distance,
D=(2/60)*80 miles
=8/3 miles
Train B catches 90-80=10 miles every 60 minutes, so
time required to catch up
=(8/3)/10 *60 minutes.
= 16 minutes

I will leave it to you to calculate the time B will catch up with A>

Answer 2

Train A has a lead of 12 min.

RT = D
T = time train B
T + .20 = time train A
90T = distance train B
80(T + .20) = distance train A

80(T + .20) = 90T
80T + 16 = 90T
16 = 10T
T = 1.6 hours

train B overtake train A = 1.6 hours

Answer 3

Tracy, go with helper's answer. I used wrong data.