Not quite.
Make a sketch, let P be the point where they meet.
Let YP = x, then ZP = 512-x
the difference in their times is 1 hour, so ..
x/32 - (512-x)/64 = 1
2x - 512 + x = 64
3x = 576
x = 192
time = 192/32 hours or 6 hours
Town Y and town Z were 512km apart. Car A left Town Y for town Z at a speed of 32km/h. An hour later, car B left Town Z for Town Y at twice of car A's speed. How long would it take for the two cars to pass each other after Car A left Town Y?
Please check
Car A time = 512/32 = 16 hrs
Car B time= 512/64 = 8hrs
So they pass each other at 8 hours???
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