town population percentage

change
Pleasantville x -2%
amity center y +5%
harmony corners z +7%

Population for Pleasantville if x = 30,250

Population- Amity if y = 7,500

Population for Harmony Corners if z = x-y

1 answer

If the population of Pleasantville (x) is 30,250 and it decreases by 2%, the new population would be:

New population of Pleasantville = x - (2/100)x
New population of Pleasantville = 30,250 - (2/100) * 30,250
New population of Pleasantville = 30,250 - 605
New population of Pleasantville = 29,645

If the population of Amity Center (y) is 7,500 and it increases by 5%, the new population would be:

New population of Amity Center = y + (5/100)y
New population of Amity Center = 7,500 + (5/100) * 7,500
New population of Amity Center = 7,500 + 375
New population of Amity Center = 7,875

If the population of Harmony Corners (z) is equal to the difference between the population of Pleasantville (x) and Amity Center (y), the population would be:

Population of Harmony Corners = x - y
Population of Harmony Corners = 30,250 - 7,500
Population of Harmony Corners = 22,750
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