Figure the moles in the H2SO4
moles= mass/molmassH2SO4
That is Molarity1
M1*V1=M2*V2
solve for V2
To what volume must a solution of 83.1 g H2SO4 in 505.3 mL of solution be diluted to give a 0.28 M solution?
I do not understand this problem. Also as a hint the professor said to use M1V1= M2V2.
2 answers
Figure the moles in the H2SO4
moles= mass/molmassH2SO4
That is Molarity1
M1*V1=M2*V2=molesabove
solve for V2
moles= mass/molmassH2SO4
That is Molarity1
M1*V1=M2*V2=molesabove
solve for V2