To what temperature must a given mass of Nitrogen at zero degree celsius be heated to double its volume and pressure?

Answer 1

initial T = 0+273

P V= n R T
same n and R so
2P * 2V = n R (4T)
4*273 = 1092 K
which is
1092-273 = 819 C

Answer 2

T1=273 T2=546 V1=0 V2=0 Therefore V1 * T2=T1 * V2 V1 * 546=273 * V2 V1 divide by V2=273 divide by 546 answer is 0.5cm

Answer 3

p1v1=p2v2
P1=