To find the constant percent rate of change of the exponential function \( y = 650(0.75)^{0.6t} \), we can rewrite it in the standard exponential form \( y = A e^{kt} \).
First, note that \( 0.75 \) can be expressed in terms of \( e \) as follows:
\[ 0.75 = e^{\ln(0.75)} \]
Thus, we can rewrite the function as:
\[ y = 650 \cdot e^{0.6 \ln(0.75) t} \]
This means we have \( k = 0.6 \ln(0.75) \).
Now we can calculate \( \ln(0.75) \):
\[ \ln(0.75) \approx -0.28768 \]
Then:
\[ k = 0.6 \cdot (-0.28768) \approx -0.172608 \]
The constant percent rate of change can be found using the formula \( r = e^{k} - 1 \). First, we need to find \( e^{-0.172608} \):
\[ e^{-0.172608} \approx 0.8403 \]
Now calculate \( r \):
\[ r = 0.8403 - 1 \approx -0.1597 \]
To convert this to a percentage, we multiply by 100:
\[ \text{Rate of change} \approx -15.97% \]
Rounding to the nearest whole percentage, the constant percent rate of change is approximately:
\[ \boxed{-16%} \]