The force constant is part 1 is just the spring constant so you would just rearrange the potential equation of
Ep = 1/2kx^2 to Ep/0.5x^2 = k
so 16 / 0.5 x 0.007^2
and that gives you k = 6530.6 N/m
part 2
you need to use hooke's law F=kx
so 6530.6 x 0.07
which means F = 457.1 N
part 3
you just use the potential equation again Ep=1/2kx^2
so Ep = 0.5 x 6530.6 x (-0.04)^2
Ep = 5.2 J
part 4
and finally use F = -kx
F = -(-0.04) x 6530.6
so F = 261.2 N
To stretch a spring 7.00 cm from its unstretched length, 16.0 J of work must be done.
What is the force constant of this spring?
What magnitude force is needed to stretch the spring 7.00 cm from its unstretched length?
How much work must be done to compress this spring 4.00 {\rm cm} from its unstretched length?
What force is needed to stretch it this distance?
F =
1 answer
1 answer