To solve the inequality \( 5(2k - 3) \geq -3(4 - 3k) \), we will first simplify both sides of the inequality.

Question

1. Distribute on both sides:
\[
5(2k) - 5(3) \geq -3(4) + 3(3k)
\]
This simplifies to:
\[
10k - 15 \geq -12 + 9k
\]

2. Next, we will move all the terms involving \( k \) to one side and the constant terms to the other side. We do this by subtracting \( 9k \) from both sides:
\[
10k - 9k - 15 \geq -12
\]
This simplifies to:
\[
k - 15 \geq -12
\]

3. Now, add 15 to both sides of the inequality:
\[
k - 15 + 15 \geq -12 + 15
\]
This simplifies to:
\[
k \geq 3
\]

The solution to the inequality \( 5(2k - 3) \geq -3(4 - 3k) \) is:
\[
k \geq 3
\]
make this like a 6th grader wrote it

Answer 1

Sure! Let's break it down in a simpler way that's easy to understand:

We want to solve the inequality \( 5(2k - 3) \geq -3(4 - 3k) \).

1. First, we need to get rid of the parentheses. To do that, we will distribute (or multiply it out) on both sides:

   On the left side: \[ 5(2k) - 5(3) = 10k - 15 \]

   On the right side: \[ -3(4) + (-3)(-3k) = -12 + 9k \]

   So now we rewrite the inequality: \[ 10k - 15 \geq -12 + 9k \]

2. Next, let's move all the \( k \) terms to one side and the numbers (constants) to the other side. We do this by subtracting \( 9k \) from both sides: \[ 10k - 9k - 15 \geq -12 \]

   This simplifies to: \[ k - 15 \geq -12 \]

3. Now, let's get \( k \) by itself by adding 15 to both sides: \[ k - 15 + 15 \geq -12 + 15 \]

   After we add, we have: \[ k \geq 3 \]

So, the final answer is: \[ k \geq 3 \] This means that \( k \) can be 3 or any number bigger than 3!