Asked by jucewrldfr
To solve the inequality \( 5(2k - 3) \geq -3(4 - 3k) \), we will first simplify both sides of the inequality.
1. Distribute on both sides:
\[
5(2k) - 5(3) \geq -3(4) + 3(3k)
\]
This simplifies to:
\[
10k - 15 \geq -12 + 9k
\]
2. Next, we will move all the terms involving \( k \) to one side and the constant terms to the other side. We do this by subtracting \( 9k \) from both sides:
\[
10k - 9k - 15 \geq -12
\]
This simplifies to:
\[
k - 15 \geq -12
\]
3. Now, add 15 to both sides of the inequality:
\[
k - 15 + 15 \geq -12 + 15
\]
This simplifies to:
\[
k \geq 3
\]
The solution to the inequality \( 5(2k - 3) \geq -3(4 - 3k) \) is:
\[
k \geq 3
\]
make this like a 6th grader wrote it
1. Distribute on both sides:
\[
5(2k) - 5(3) \geq -3(4) + 3(3k)
\]
This simplifies to:
\[
10k - 15 \geq -12 + 9k
\]
2. Next, we will move all the terms involving \( k \) to one side and the constant terms to the other side. We do this by subtracting \( 9k \) from both sides:
\[
10k - 9k - 15 \geq -12
\]
This simplifies to:
\[
k - 15 \geq -12
\]
3. Now, add 15 to both sides of the inequality:
\[
k - 15 + 15 \geq -12 + 15
\]
This simplifies to:
\[
k \geq 3
\]
The solution to the inequality \( 5(2k - 3) \geq -3(4 - 3k) \) is:
\[
k \geq 3
\]
make this like a 6th grader wrote it
Answers
Answered by
GPT-4o mini
Sure! Let's break it down in a simpler way that's easy to understand:
We want to solve the inequality \( 5(2k - 3) \geq -3(4 - 3k) \).
1. **First, we need to get rid of the parentheses**. To do that, we will distribute (or multiply it out) on both sides:
On the left side:
\[
5(2k) - 5(3) = 10k - 15
\]
On the right side:
\[
-3(4) + (-3)(-3k) = -12 + 9k
\]
So now we rewrite the inequality:
\[
10k - 15 \geq -12 + 9k
\]
2. **Next, let's move all the \( k \) terms to one side** and the numbers (constants) to the other side. We do this by subtracting \( 9k \) from both sides:
\[
10k - 9k - 15 \geq -12
\]
This simplifies to:
\[
k - 15 \geq -12
\]
3. **Now, let's get \( k \) by itself** by adding 15 to both sides:
\[
k - 15 + 15 \geq -12 + 15
\]
After we add, we have:
\[
k \geq 3
\]
So, the final answer is:
\[
k \geq 3
\]
This means that \( k \) can be 3 or any number bigger than 3!
We want to solve the inequality \( 5(2k - 3) \geq -3(4 - 3k) \).
1. **First, we need to get rid of the parentheses**. To do that, we will distribute (or multiply it out) on both sides:
On the left side:
\[
5(2k) - 5(3) = 10k - 15
\]
On the right side:
\[
-3(4) + (-3)(-3k) = -12 + 9k
\]
So now we rewrite the inequality:
\[
10k - 15 \geq -12 + 9k
\]
2. **Next, let's move all the \( k \) terms to one side** and the numbers (constants) to the other side. We do this by subtracting \( 9k \) from both sides:
\[
10k - 9k - 15 \geq -12
\]
This simplifies to:
\[
k - 15 \geq -12
\]
3. **Now, let's get \( k \) by itself** by adding 15 to both sides:
\[
k - 15 + 15 \geq -12 + 15
\]
After we add, we have:
\[
k \geq 3
\]
So, the final answer is:
\[
k \geq 3
\]
This means that \( k \) can be 3 or any number bigger than 3!
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