To raise money, the student council at a local middle school is hosting a talent show. Tickets are sold for $5.00 for students (x) and $8.00 for adults (y). The goal is to raise a total of $1,575.00. Which of the following is a viable solution for the number of student and adult tickets that can be sold?(1 point)

Question

Responses

(371,−35)
left parenthesis negative 371 comma negative 35 right parenthesis

(81,146.25)
left parenthesis 81 comma 146.25 right parenthesis

(125,115)
left parenthesis 125 comma 115 right parenthesis

(115,125)

Answer 1

To determine if the given pairs of values for student tickets (x) and adult tickets (y) can raise a total of $1,575.00, we can use the following equation based on the ticket prices:

\[ 5x + 8y = 1575 \]

Now let's check each of the provided options:

1. (371, -35) \[ 5(371) + 8(-35) = 1855 - 280 = 1575 \]

   • However, y = -35 is not a valid solution since you cannot sell negative tickets.

2. (81, 146.25) \[ 5(81) + 8(146.25) = 405 + 1170 = 1575 \]

   • Although this satisfies the equation, y = 146.25 is not a valid solution since you cannot sell a fraction of a ticket.

3. (125, 115) \[ 5(125) + 8(115) = 625 + 920 = 1545 \]

   • This does not satisfy the equation as the total is not $1,575.

4. (115, 125) \[ 5(115) + 8(125) = 575 + 1000 = 1575 \]

   • This does satisfy the equation.

The only viable solution for the number of student and adult tickets that can be sold is (115, 125).