To prove that triangle \( ABC \) is congruent to triangle \( A''B''C'' \) using the ASA (Angle-Side-Angle) criterion through rigid motions, we need to ensure that the corresponding angles and the included side between those angles in both triangles are preserved. This means we should find a way to transform triangle \( ABC \) into triangle \( A''B''C'' \) through a series of rotations and reflections that maintains distances and angles.
Given the options:
Option A: Rotate triangle ABC 90 degrees (counterclockwise) about vertex C, and then reflect triangle \( A'B'C' \) across line \( CA' \).
Option B: Rotate triangle ABC - 90 degrees (clockwise) about vertex C, and then reflect triangle \( A'B'C' \) across line \( B'C \).
Option C: Rotate triangle ABC - 90 degrees (clockwise) about vertex C, and then reflect triangle \( A'B'C' \) across line \( CA' \).
Option D: Rotate triangle ABC 360 degrees (counterclockwise), and then reflect triangle \( A'B'C' \) across line \( B'C \).
Among these options, option A appears to correctly align with the ASA criterion because:
- The initial rotation around point \( C \) preserves the relative positions of points \( A \) and \( B \) with respect to \( C \).
- Reflecting around line \( CA' \) corresponds to matching the angles and ensuring \( A \) aligns with \( A'' \) while maintaining the side length between \( C \) and the new position of \( A \).
Thus, the proper transformation that follows the ASA criterion through rigid motions is best captured by Option A.