(C) III only
because M=mol/L, and mol=grams/molar mass (dimensional analysis).
Assuming the same grams for each solution, a higher molar mass would yield a smaller number of moles when divided in the mol=grams/molar mass equation.
This same number of moles will be divided by the same number of liters (in the M=mol/L equation). The number of liters is therefore also a smaller value in order to match the number of moles to eventually get a molarity of 1.0
To neutralize a solution of NaOH and use the least volume of acid, you should select
I. 1.0M HCl
II. 1.0 M HC(2)H(3)O(2)
III. 1.0 M H(2)SO(4)
(A) I only
(B) II only
(C) III only
(D) I and II use equal and lesser volumes.
(E) I, II, and III use the same volumes of acids
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