revenue = (40 + 5 x) (60 - 3 x) = 2400 + 180 x - 15 x^2
the max is on the axis of symmetry of the parabola
... xmax = -b / (2 a) = -180 / -30 = 6
substitute into the revenue equation to find the max price and revenue
to increase revenue, a sports store has decided to increase the cost of a baseball glove. they expect that for every 5$ increase in price from the current price of 40$, three fewer gloves will be sold per week than the current 60 per week. what is the selling price that will maximize the revenue and what is the maximum revenue?
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