To find the value of \( k \) in the equation \( 7 + 2k^2 = 25 \), we can follow these steps:

Question

1. Start with the equation:
\[
7 + 2k^2 = 25
\]

2. Subtract 7 from both sides:
\[
2k^2 = 25 - 7
\]
\[
2k^2 = 18
\]

3. Divide both sides by 2:
\[
k^2 = \frac{18}{2}
\]
\[
k^2 = 9
\]

4. Take the square root of both sides:
\[
k = \pm 3
\]

Thus, the solution set for \( k \) is:
\[
k = 3 \quad \text{or} \quad k = -3
\]

So the solution set is \( \{ 3, -3 \} \).
make this like a 6th grader wrote it

Answer 1

To find the value of \( k \) in the equation \( 7 + 2k^2 = 25 \), we can do the following steps:

1. We start with the equation: \[ 7 + 2k^2 = 25 \]

2. Next, we want to get rid of the 7 on the left side, so we subtract 7 from both sides: \[ 2k^2 = 25 - 7 \] This gives us: \[ 2k^2 = 18 \]

3. Now, we need to make \( k^2 \) by itself, so we divide both sides by 2: \[ k^2 = \frac{18}{2} \] Which simplifies to: \[ k^2 = 9 \]

4. Finally, we take the square root of both sides to find \( k \): \[ k = \pm 3 \] This means that \( k \) can be either 3 or -3.

So, the answer is: \[ k = 3 \quad \text{or} \quad k = -3 \]

In simpler words, the values of \( k \) are 3 and -3! The solution set is \( { 3, -3 } \).