To find the solution set of the equations \(2x - 3 = 5\) and the inequality \(5x + 3 > -12\), we will solve each one separately and then find the intersection of their solutions.

1. **Solve the equation \(2x - 3 = 5\)**:

\[
2x - 3 = 5
\]
Add 3 to both sides:
\[
2x = 5 + 3
\]
\[
2x = 8
\]
Divide by 2:
\[
x = 4
\]

2. **Solve the inequality \(5x + 3 > -12\)**:

\[
5x + 3 > -12
\]
Subtract 3 from both sides:
\[
5x > -12 - 3
\]
\[
5x > -15
\]
Divide by 5 (and since 5 is a positive number, the inequality remains the same):
\[
x > -3
\]

3. **Combine the solutions**:

The solution to the equation \(2x - 3 = 5\) gives us \(x = 4\).
The solution to the inequality \(5x + 3 > -12\) gives us \(x > -3\).

Since \(x = 4\) satisfies \(x > -3\), the combined solution set is simply \(x = 4\).

**Final Answer**: The solution set is \(\{4\}\).

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1 answer

To solve the equations \(2x - 3 = 5\) and \(5x + 3 > -12\):

  1. Solve the equation: \[ 2x - 3 = 5 \implies 2x = 8 \implies x = 4 \]

  2. Solve the inequality: \[ 5x + 3 > -12 \implies 5x > -15 \implies x > -3 \]

  3. Combine the solutions: The solution \(x = 4\) satisfies the inequality \(x > -3\).

Final Answer: The solution set is \({4}\).