To find the distance from the house at point D to the house at point E, a surveyor measures ÚDFE, which he finds is 73‹40'. The distance from the house at point D to point F is 15 ft, and the distance from point F to the house at point E is 28 ft. How far apart are the houses?

Question

To find the distance from the house at point D to the house at point E, a surveyor measures ÚDFE, which he finds is 73‹40'. The distance from the house at point D to point F is 15 ft, and the distance from point F to the house at point E is 28 ft. How far apart are the houses?

Steve · Answer

this one is just like the one with bearings. Use law of cosines: DE² = FD² + FE² - 2*FD*FE*cosF DE² = 225 + 784 - 2*15*28*cos(73.666666) DE² = 773 DE = 28

tori · Answer

Thank you so much!

To find the distance from the house at point D to the house at point E, a surveyor measures �ÚDFE, which he finds is 73�‹40'. The distance from the house at point D to point F is 15 ft, and the distance from point F to the house at point E is 28 ft. How far apart are the houses?