The correct answer is d. either B or c would work.
To extract aniline from a solution of chloroform, one would need a base to convert the aniline into its anionic form. Both aqueous NaOH (option b) and aqueous NaHCO3 (option c) can act as bases and convert aniline into its anionic form, which would then be soluble in the aqueous phase and can be separated from the chloroform.
To extract aniline (C6H5NH2) from a solution of chloroform, one would use:
a. aqueous HCL
b. aqueous NaOH
c. aqueous NaHCO3
d. either B or c would work
3 answers
why would it not be aqueous HCL
My apologies for the confusion. To extract aniline from a solution of chloroform, one would need to use aqueous HCl (option a) instead of aqueous NaOH or aqueous NaHCO3.
Aqueous HCl can protonate the aniline molecules, converting them into their protonated form (C6H5NH3+) which is soluble in the aqueous phase. This allows for the separation of aniline from chloroform.
Therefore, the correct answer is a. aqueous HCl.
Aqueous HCl can protonate the aniline molecules, converting them into their protonated form (C6H5NH3+) which is soluble in the aqueous phase. This allows for the separation of aniline from chloroform.
Therefore, the correct answer is a. aqueous HCl.