Ask a New Question
Search
to evaluate (integral) 3x^2 cos (2x^3-4) dx, it is necessary to let
A. u=3x^2
B. u=6x
C. u=2x^3-4
D. u=6x^2
1 answer
C
then du = 2(3x^2) dx
Similar Questions
Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if it is convergent or divergent).
I know how to find the
2 answers
1. Express the given integral as the limit of a Riemann sum but do not evaluate:
integral[0 to 3]((x^3 - 6x)dx) 2.Use the
1 answer
Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if it is convergent or divergent).
I know how to find the
2 answers
a) Let f(z) = z^2 and γ(t) = 1 + it^3, t ∈ [0,1].
i) Write out the contour integral ∫γ f(z)dz as an integral with respect
2 answers
more similar questions