To find out how much force Joaquin saves by using the lever, we first need to determine the force he would need to apply when using the lever.
Given that the mechanical advantage (MA) of the lever is 3, we can use the formula:
\[ \text{Force applied with lever} = \frac{\text{Weight of the crate}}{\text{Mechanical Advantage}} \]
In this case, the weight of the crate is 312 N.
So,
\[ \text{Force applied with lever} = \frac{312 \text{ N}}{3} = 104 \text{ N} \]
Now, to find out how much force he saves, we subtract the force applied with the lever from the force he would need to apply without the lever:
\[ \text{Force saved} = \text{Original Force} - \text{Force with lever} = 312 \text{ N} - 104 \text{ N} = 208 \text{ N} \]
Therefore, the answer is:
208 N