To determine which of the ordered pairs is a solution to the equation \(2.5y - 3x = 10\), we can substitute each pair into the equation.

Question

1. For the pair \((5, -2)\):
\[
2.5(-2) - 3(5) = -5 - 15 = -20 \quad \text{(not equal to 10)}
\]

2. For the pair \((-5, 2)\):
\[
2.5(2) - 3(-5) = 5 + 15 = 20 \quad \text{(not equal to 10)}
\]

3. For the pair \((5, 2)\):
\[
2.5(2) - 3(5) = 5 - 15 = -10 \quad \text{(not equal to 10)}
\]

4. For the pair \((-5, -2)\):
\[
2.5(-2) - 3(-5) = -5 + 15 = 10 \quad \text{(equal to 10)}
\]

Therefore, the ordered pair that is a solution to the equation \(2.5y - 3x = 10\) is \((-5, -2)\).
make this like a 6th grader wrote it

Answer 1

To figure out which of these pairs of numbers solves the equation \(2.5y - 3x = 10\), we can plug each pair into the equation.

1. For the pair \((5, -2)\): \[ 2.5(-2) - 3(5) = -5 - 15 = -20 \quad \text{(not equal to 10)} \]

2. For the pair \((-5, 2)\): \[ 2.5(2) - 3(-5) = 5 + 15 = 20 \quad \text{(not equal to 10)} \]

3. For the pair \((5, 2)\): \[ 2.5(2) - 3(5) = 5 - 15 = -10 \quad \text{(not equal to 10)} \]

4. For the pair \((-5, -2)\): \[ 2.5(-2) - 3(-5) = -5 + 15 = 10 \quad \text{(equal to 10)} \]

So, the ordered pair that works with the equation \(2.5y - 3x = 10\) is \((-5, -2)\).