The monoprotic acid is HA.
HA + NaOH ==> NaA + H2O
mols NaOH = M x L = ?
(note: volume NaOH = 13.41-2.19 = ? mL and convert to L).
Then mols HA = mols NaOH
M HA = mols HA/L HA.
To determine the concentration of 10.31mL of an unknown solution of a monoprotic acid, it is titrated with 0.172M sodium hydroxide. The initial reading on the buret of sodium hydroxide is 2.19mL. The final reading is 13.41mL. What is the concentration of the unknown acid?
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