To determine the compound amount of an investment of $10,000 with an interest rate of 6% compounded monthly after 4 years requires you to use a table factor that goes beyond the Compound Interest Table. Calculate the new table factor for this investment

Answer 1

( "Interest tables" in 2013 ?
Calculators have been in common use for over 40 years to replace those tables)

you will need (1 + .06/12)^48 = 1.005^48 = 1.27048961

amount = 10000(1 + .06/12)^48
= 10000( 1.005)^48 = $12704.89

Answer 2

I'm sorry Reiny but the answer you have provided is not the correct answer.
I am not understanding where you got your numbers from either. Could you explain?

Answer 3

As Reiny pointed out, we do not use tables for the past 40 years, so we can only guess what's shown in the tables.

My guess would be that the factor is the ratio of future/present values, namely:
1.005^48=1.270489

Note:
compound interest is calculated as:
future value=present value * (1+interest rate per period)^number of periods

Since interest is compounded every month, each period is one month.

interest rate per period (month) is 6%/12 months = 0.005
number of periods = 4 years * 12month/year=48