To determine the average height of trees in a national forest, 10 trees are randomly selected. Their heights in feet are 85.4, 87.6, 87.1, 85.6, 85.9, 85.3, 84.9, 83.7, 84.0, and 85.2. To ensure the accuracy of the data, another set of 10 trees is randomly selected. Their heights are 87.1, 88.0, 84.2, 85.3, 86.5, 84.2, 83.2, 84.1, 85.2, and 87.3. What is the difference between the mean height of trees of these two random samples?

Answer 1

First, let's calculate the mean height of the first set of trees:

(85.4 + 87.6 + 87.1 + 85.6 + 85.9 + 85.3 + 84.9 + 83.7 + 84.0 + 85.2) / 10 = 85.37 feet

Next, let's calculate the mean height of the second set of trees:

(87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 83.2 + 84.1 + 85.2 + 87.3) / 10 = 85.81 feet

Now, let's find the difference between the mean height of the two sets of trees:

85.81 - 85.37 = 0.44 feet

Therefore, the difference between the mean height of the two random samples is 0.44 feet.

Answer 2

Try again

Answer 3

Apologies for the mistake in the previous calculation. Let's recalculate it:

Mean height of the first set of trees:
(85.4 + 87.6 + 87.1 + 85.6 + 85.9 + 85.3 + 84.9 + 83.7 + 84.0 + 85.2) / 10 = 85.17 feet

Mean height of the second set of trees:
(87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 83.2 + 84.1 + 85.2 + 87.3) / 10 = 85.21 feet

Now, let's find the difference between the mean height of the two sets of trees:

85.21 - 85.17 = 0.04 feet

Therefore, the difference between the mean height of the two random samples is 0.04 feet.