Sure! Let's make it simpler for a 6th grader to understand.
Imagine Dezeree has a gift card worth $100. She wants to buy some sweaters that cost $27.50 each. To find out how many sweaters she can buy, we can set up a little math problem:
Let \( x \) be the number of sweaters. The total cost to buy \( x \) sweaters would be:
\[ 27.50 \times x = 100 \]
Now, we want to find out what \( x \) is, so we will divide both sides by 27.50 to solve for \( x \):
\[ x = \frac{100}{27.50} \]
Now, let’s do that division:
\[ x = 3.63636363636 \]
Since Dezeree can't buy a part of a sweater (that would be silly!), we round down to the nearest whole number. So, she can buy 3 sweaters.
Next, let’s find out how much money she will actually spend on those 3 sweaters:
\[ \text{Total cost} = 27.50 \times 3 = 82.50 \]
This means she spends $82.50 on 3 sweaters. So, how much money does she have left on her gift card?
To find that out, we can subtract the total cost from the amount on her gift card:
\[ 100 - 82.50 = 17.50 \]
That means Dezeree still has $17.50 left on her gift card!
Now, just to check if she could buy one more sweater (4 sweaters):
\[ \text{Cost for 4 sweaters} = 27.50 \times 4 = 110 \]
Oh no! $110 is more than her $100 gift card, so she cannot afford 4 sweaters.
Conclusion
So, Dezeree can buy a maximum of 3 sweaters for a total cost of $82.50, and she will have $17.50 left on her gift card.