To completely factor 5c^2-24cd-5d^2, I used the following steps: (5c d)(c 5d) to give terms,ignoring signs,5c^2,cd,25cd,5d^2.
+cd-25cd.
(5c+d)(c-5d)
Please correct,if necessary,and show correct way to show this problem.
Thank You.
2 answers
your solution looks fine
5 c ^ 2 - 24 c d - 5 d ^ 2
Rewrite - 24 c d as - 25 c d + c d
Now:
5 c ^ 2 - 24 c d - 5 d ^ 2 =
5 c ^ 2 - 25 c d + c d - 5 d ^ 2 =
5 c ^ 2 + c d - 25 c d - 5 d ^ 2 =
5 c ^ 2 + c d - ( 25 c d + 5 d ^ 2 ) =
c ( 5 c + d ) - 5 d ( 5 c + d ) =
( 5 c + d ) ( c - 5 d )
Your solution is correct.
Rewrite - 24 c d as - 25 c d + c d
Now:
5 c ^ 2 - 24 c d - 5 d ^ 2 =
5 c ^ 2 - 25 c d + c d - 5 d ^ 2 =
5 c ^ 2 + c d - 25 c d - 5 d ^ 2 =
5 c ^ 2 + c d - ( 25 c d + 5 d ^ 2 ) =
c ( 5 c + d ) - 5 d ( 5 c + d ) =
( 5 c + d ) ( c - 5 d )
Your solution is correct.
2 answers