To calculate the allele frequencies in the population, we can assign the dominant allele (gray wings) as "G" and the recessive allele (white wings) as "g."

Question

Given that 20% are homozygous dominant (GG), 20% are heterozygous (Gg), and 60% are homozygous recessive (gg), we can determine the allele frequencies.

The frequency of the dominant allele (G) can be calculated as follows:

( 2 ^ * frequency of GG individuals) + (frequency of Gg individuals)

=( 2 ^ * 0.20)+0.20 = 0.4 + 0.2

= 0.6
The frequency of the recessive allele (g) can

be determined by subtracting the frequency of the dominant allele (G) from 1:

1 - 0.6 = 0.4

The allele frequencies in this population are 0.60 for G and 0.40 for g.

We can use the allele frequencies calculated earlier.

The expected frequency of GG individuals is (frequency of G)^2 = 0.60^2 = 0.36 (or 36%).

The expected frequency of Gg individuals is 2* (frequency of G) * (frequency of g )=2 * 0.60^ * 0.4 = 0.48 (or 48%).

The expected frequency of gg individuals is (frequency of g)^ 2 = 0.4 ^ 2 = 0.16 (or 16%).

The observed genotype frequencies differ from the expected frequencies (36% GG, 48% Gg, and 16% gg). The population is not in Hardy-Weinberg equilibrium
Make the above equation short but I clide everything

Answer 1

To calculate allele frequencies, assign dominant allele (G) and recessive allele (g). Frequencies: 20% GG, 20% Gg, 60% gg. Allele frequencies: G=0.60, g=0.40. Expected frequencies: GG=36%, Gg=48%, gg=16%. Population not in Hardy-Weinberg equilibrium.